C Program to find out leap year

Write a program to find entered year is a leap year or not a leap year.

#include<conio.h>
#include<stdio.h>
void main()
{
int year;
clrscr();
printf("Enter Year:");
scanf("%d",&year);
if(year%4==0 || year%400==0)
{
printf("%d is leap year...!!!",year);
}
else
{
printf("%d is not a leap year...!!!",year);
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 24

Pattern 24

write a prog. to print following pattern

A

AB

ABC

ABCD

ABCDE

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=66,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
m=65;
for(j=0;j<=i;j++,m++)
{
printf("%c",m);
if(m>=90)
{
m=64;
}
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 23

Pattern 23

write a prog. to print following pattern

B

BD

BDF

BDFH

BDFHJ

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=66,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
m=66;
for(j=0;j<=i;j++,m+=2)
{
printf("%c",m);
if(m>=90)
{
m=64;
}
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 22

Pattern 22

write a prog. to print following pattern

A

AC

ACE

ACEG

ACEGI

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=65,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
m=65;
for(j=0;j<=i;j++,m+=2)
{
printf("%c",m);
if(m>88)
{
m=63;
}
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 21

Pattern 21

write a prog. to print following pattern

1

35

791

3579

13579

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=1,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++,m+=2)
{
if(m>9)
{
m=1;
}
printf("%d",m);
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 20

Pattern 20

write a prog. to print following pattern

0

02

024

0246

02468

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{
m=0;
for(j=1;j<=i;j++,m+=2)
{
if(m>8)
{
m=0;
}
printf("%d",m);
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 19

Pattern 19

write a prog. to print following pattern

1

13

135

1357

13579

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{
m=1;
for(j=1;j<=i;j++,m+=2)
{
if(m>9)
{
m=1;
}
printf("%d",m);
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 18

Pattern 18

write a prog. to print following pattern

0

22

444

6666

88888

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++,m+=2)
{
if(m>8)
{
m=0;
}
for(j=1;j<=i;j++)
{
printf("%d",m);
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 17

Pattern 17

write a prog. to print following pattern

1

33

555

7777

99999

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=1,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++,m+=2)
{
if(m>9)
{
m=1;
}
for(j=1;j<=i;j++)
{
printf("%d",m);
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 16

Pattern 16

write a prog. to print following pattern

A

BB

CCC

DDDD

EEEEE

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=65,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
for(j=0;j<=i;j++)
{
printf("%c",m);
}
printf("\n");
m++;
if(m>90)
{
m=64;
}
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 15

Pattern 15

write a prog. to print following pattern

A

BC

DEF

GHIJ

KLMNO

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=65,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
for(j=0;j<=i;j++)
{
printf("%c",m);
m++;
if(m>90)
{
m=64;
}
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 14

Pattern 14

write a prog. to print following pattern

1

22

333

4444

55555


#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,m=1,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++,m+=2)
{
if(m>9)
{
m=1;
}
for(j=1;j<=i;j++)
{
printf("%d",m);
}
printf("\n");
}
getch();

}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 13

Pattern 13

write a prog. to print following pattern

1

10

101

1010

10101



#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=0;i<n;i++)
{
for(j=0;j<=i;j++)
{
if(j%2==0)
printf("1");
else
printf("0");
}
printf("\n");
}
getch();
}


/******************   OR   ******************/



#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{
for(j=1;j<=i;j++)
{
printf("%d",(j%2));
        }
printf("\n");
}
getch();

}



O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 12

Pattern 12

write a prog. to print following pattern

1
23
456
7890
12345



#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j,k;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
k=1;
for(i=0;i<n;i++)
{
for(j=0;j<=i;j++)
{
if(k>9)
{
k=0;
}
printf("%d",k);
k++;
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 11

Pattern 11

write a prog. to print following pattern, for n=5

*

***

*****

*******

*********

*******

*****

***

*

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{

for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("*");
}
for(j=2;j<=i;j++)
{
printf("*");
}
printf("\n");
}
n=n-1;
for(i=n;i>=1;i--)
{
for(j=i;j<=n;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("*");
}
for(j=2;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}


O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 10

Pattern 10
Write a prog. to print following pattern, for n=5

*********
  *******
   *****
    ***
      *
#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=n;i>=1;i--)
{
for(j=i;j<n;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("*");
}
for(j=2;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 9

Pattern 9
Write a prog. to print following pattern for n=5

        *
      ***
    *****
  *******
*********

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{

for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("*");
}
for(j=2;j<=i;j++)
{
printf("*");
}
printf("\n");
}
getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 8

Pattern 8

Write A Prog. To Print Following Pattern

* * * * *
 * * * *
  * * *
   * *
    *

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=n;i>=1;i--)
{
for(j=i;j<n;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("* ");
}
printf("\n");
}

getch();
}

O/P:

C Programming for beginners, Patterns using nested for loop, Pattern 7

Pattern 7
Write a prog. to print following pattern

       *
     * *
   * * *
 * * * *
* * * * *

#include<conio.h>
#include<stdio.h>
void main()
{
int n=0,i,j;
clrscr();
printf("Enter N:");
scanf("%d",&n);
printf("\n\n");
for(i=1;i<=n;i++)
{

for(j=1;j<=n-i;j++)
{
printf(" ");
}
for(j=1;j<=i;j++)
{
printf("* ");
}
printf("\n");
}
getch();
}


O/P: